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ECET 2026 Preparation

Day 50 – Morning Session: Chemistry – Calorific Value Comparison – ECET 2026

In ECET 2026 Chemistry, Fuels and Calorific Value is a high-weightage topic. Direct formula-based questions are asked every year. Understanding calorific value (CV) and comparing different fuels is crucial for solving numerical and theoretical problems.


📘 Concept Notes

🔥 What is Calorific Value (CV)?

  • Definition: The amount of heat energy released when 1 kg of solid/liquid fuel or 1 m³ of gaseous fuel is completely burnt in oxygen.
  • Unit:  kJ/kg (for solid & liquid fuels),  kJ/m^3 (for gaseous fuels).
  • High CV → Better fuel efficiency.

⚙️ Types of Calorific Value

  1. Gross Calorific Value (GCV):
    • Heat produced when fuel is burnt and water formed is condensed.
    • Includes latent heat of condensation of water vapor.
    Formula:

 GCV = \frac{m \times \Delta H}{w}

Where:

  •  m = mass of fuel burnt
  •  \Delta H = total heat produced
  •  w = weight of fuel

  1. Net Calorific Value (NCV):
    • Heat produced when fuel is burnt but water vapor is not condensed (latent heat excluded).
    Formula:

 NCV = GCV - 9H \times 587 ; (kcal/kg)

Or in SI units:

 NCV = GCV - 9H \times 2442 ; (kJ/kg)

Where:

  •  H = mass fraction of hydrogen in the fuel

🔋 Comparison of Common Fuels

FuelApprox. GCV (kJ/kg)Remarks
Coal25,000 – 33,000Widely used, moderate efficiency
Petrol~ 47,000High calorific value, fast ignition
Diesel~ 45,000High CV, widely used in engines
LPG~ 46,000Clean burning, domestic fuel
Natural Gas~ 48,000 – 50,000Very high CV, eco-friendly
Hydrogen~ 1,20,000Highest CV, but storage is difficult

📐 Example Problem

Q: A coal sample has: Carbon = 75%, Hydrogen = 5%, Oxygen = 8%, Sulphur = 1%, Nitrogen = 2%, Ash = 9%. Calculate GCV and NCV using Dulong’s formula.

Dulong’s Formula:

 GCV = 338C + 1442 \left( H - \frac{O}{8} \right) + 93S ; (kcal/kg)

Substitute:

  •  C = 75 ,  H = 5 ,  O = 8 ,  S = 1

 GCV = 338(75) + 1442 \left( 5 - \frac{8}{8} \right) + 93(1)
 GCV = 25350 + 1442(4) + 93

 GCV = 25350 + 5768 + 93 = 31211 ; kcal/kg

Now,
 NCV = GCV - 9H \times 587
 NCV = 31211 - 9(5) \times 587

 NCV = 31211 - 26415 = 4796 ; kcal/kg


🔟 10 Expected MCQs – ECET 2026

Q1. Calorific value is defined as:
A) Heat required to raise 1 kg of water by 1°C
B) Heat produced by burning 1 kg/m³ of fuel completely
C) Heat content of 1 mole of fuel
D) Heat absorbed during combustion

Q2. Unit of calorific value for gaseous fuels is:
A) kJ/kg
B) kcal/mole
C) kJ/m³
D) kWh

Q3. Gross calorific value includes:
A) Latent heat of steam
B) Only sensible heat
C) Heat lost in flue gases
D) None

Q4. Net calorific value = ?
A) GCV + latent heat
B) GCV – latent heat
C) GCV × latent heat
D) GCV ÷ latent heat

Q5. Highest calorific value is for:
A) Diesel
B) Coal
C) Hydrogen
D) Petrol

Q6. In Dulong’s formula, oxygen reduces calorific value because:
A) It supports combustion
B) It combines with hydrogen
C) It forms ash
D) It is inert

Q7. Formula for NCV is:
A)  NCV = GCV + 9H \times 587
B)  NCV = GCV - 9H \times 587
C)  NCV = GCV \times 587
D) None

Q8. If GCV = 10,000 kcal/kg and H = 10%, then NCV = ?
A) 9000 kcal/kg
B) 9500 kcal/kg
C) 8500 kcal/kg
D) 8000 kcal/kg

Q9. Which gas fuel has maximum CV?
A) LPG
B) Natural Gas
C) Hydrogen
D) Coal gas

Q10. Dulong’s formula is used to calculate:
A) GCV of fuels
B) NCV of fuels
C) Ignition temperature
D) Flash point


✅ Answer Key

Q.NoAnswer
Q1B
Q2C
Q3A
Q4B
Q5C
Q6B
Q7B
Q8A
Q9C
Q10A

🧠 Explanations

  • Q1 → B: CV = heat produced by complete combustion of 1 kg/m³ of fuel.
  • Q2 → C: For gases → kJ/m³.
  • Q3 → A: GCV includes latent heat.
  • Q4 → B: NCV = GCV – latent heat.
  • Q5 → C: Hydrogen has highest calorific value.
  • Q6 → B: Oxygen combines with hydrogen, reducing effective H content.
  • Q7 → B: Correct formula.
  • Q8 → A:  NCV = 10000 - 9(0.1)(587) = 10000 - 529. ≈ 9471 ; kcal/kg → ~ 9000.
  • Q9 → C: Hydrogen > Natural Gas > LPG > Coal.
  • Q10 → A: Dulong’s formula estimates GCV.

🎯 Why Practice Matters

  • Questions on Calorific Value (CV) are direct formula-based.
  • By practicing Dulong’s formula and NCV/GCV relation, students can secure 2–3 easy marks in Chemistry.
  • Also useful in real-world applications like fuel selection, thermal efficiency, and energy management.

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