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ECET 2026 ECE

Day 1 ECET 2026 ECE – AM Basics Notes, Formulas & MCQs

Concept Notes

1. Introduction to Amplitude Modulation (AM)

  • Amplitude Modulation is a technique where the amplitude of the carrier wave is varied according to the instantaneous amplitude of the message signal while the frequency remains constant.
  • Carrier: c(t) = A_c \cos(2 \pi f_c t)
  • Message signal: m(t)

2. AM Wave Equation

The general AM wave is:

 s(t) = \left[ A_c + m(t) \right] \cos(2 \pi f_c t)

Where:

  • A_c = Carrier amplitude
  • f_c = Carrier frequency
  • m(t) = Message signal (modulating signal)

For sinusoidal message m(t) = A_m \cos(2 \pi f_m t), AM wave becomes:

 s(t) = A_c \left[ 1 + \frac{A_m}{A_c} \cos(2 \pi f_m t) \right] \cos(2 \pi f_c t)


3. Modulation Index (m)

  • It measures the extent of modulation:

 m = \frac{A_m}{A_c}

Types:

  • Under-modulation:  m < 1 → safe, no distortion
  • 100% modulation:  m = 1 → maximum amplitude without distortion
  • Over-modulation:  m > 1 → distortion occurs

4. AM Wave Components

  • Carrier:  A_c \cos(2 \pi f_c t)
  • Upper sideband (USB):  \frac{m A_c}{2} \cos 2 \pi (f_c + f_m) t
  • Lower sideband (LSB):  \frac{m A_c}{2} \cos 2 \pi (f_c - f_m) t

Total AM power:

 P_{AM} = P_c \left( 1 + \frac{m^2}{2} \right)

Where:

  •  P_c = \frac{A_c^2}{2 R} → carrier power
  •  m → modulation index

5. Advantages of AM

  • Simple generation & demodulation
  • Compatible with existing broadcast systems

Disadvantages:

  • Low power efficiency (carrier consumes 2/3 of power at 100% modulation)
  • Susceptible to noise

⚙️ Formulas

AM Wave:

 s(t) = A_c \left[ 1 + m \cos(2 \pi f_m t) \right] \cos(2 \pi f_c t)

Modulation Index:

 m = \frac{A_m}{A_c}

AM Power:

 P_{AM} = P_c \left( 1 + \frac{m^2}{2} \right)

Carrier Power:

 P_c = \frac{A_c^2}{2R}

Sideband Power:

 P_{SB} = \frac{m^2 P_c}{2}

Total AM Power:

 P_{T} = P_c + P_{USB} + P_{LSB} = P_c \left( 1 + \frac{m^2}{2} \right)


🔟 10 MCQs

Q1. In AM, the frequency of the carrier:
a) Varies with message signal
b) Remains constant
c) Becomes zero
d) Increases linearly

Q2. The modulation index is:
a)  A_c / A_m
b)  A_m / A_c
c)  P_c / P_m
d)  f_c / f_m

Q3. Total AM power for 100% modulation is:
a)  1.5 P_c
b)  2 P_c
c)  0.5 P_c
d)  P_c

Q4. AM wave contains:
a) Only carrier
b) Carrier + 1 sideband
c) Carrier + 2 sidebands
d) Only sidebands

Q5. For over-modulation:
a)  m < 1
b)  m = 1
c)  m > 1
d)  m = 0

Q6. Upper sideband frequency:
a)  f_c - f_m
b)  f_c + f_m
c)  f_m
d)  f_c

Q7. AM is most susceptible to:
a) Amplitude noise
b) Phase noise
c) Frequency variation
d) Thermal noise

Q8. Carrier power:
 P_c = ?
a)  A_c^2 / R
b)  A_c^2 / 2 R
c)  A_m^2 / 2 R
d)  A_c A_m / R

Q9. Sideband power in AM:
 P_{SB} = ?
a)  P_c
b)  m^2 P_c / 2
c)  m P_c
d)  P_c / m

Q10. Advantage of AM:
a) High efficiency
b) Simple generation and detection
c) Immune to noise
d) No carrier needed


✅ Answer Key

Q NoAnswer
Q1b
Q2b
Q3a
Q4c
Q5c
Q6b
Q7a
Q8b
Q9b
Q10b

🧠 Explanations

  • Q1: Carrier frequency remains constant in AM → (b)
  • Q2:  m = A_m / A_c → (b)
  • Q3:  P_{AM} = P_c (1 + m^2/2) = P_c (1 + 1/2) = 1.5 P_c
  • Q4: AM has carrier + 2 sidebands → (c)
  • Q5: Over-modulation →  m > 1 → (c)
  • Q6: Upper sideband =  f_c + f_m → (b)
  • Q7: AM affected by amplitude noise → (a)
  • Q8: Carrier power =  A_c^2 / 2 R → (b)
  • Q9: Sideband power =  m^2 P_c / 2 → (b)
  • Q10: AM is simple to generate & detect → (b)

🎯 Motivation / Why Practice Matters

  • AM forms the basis of analog communication.
  • ECET 2026 often tests: modulation index, AM power, sidebands.
  • Mastering AM formulas ensures fast numerical solving and conceptual clarity in the exam.

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