Over 10 years we helping companies reach their financial and branding goals. Onum is a values-driven SEO agency dedicated.

CONTACTS
ECET 2026 ECE

Day 2 ECET 2026 ECE – Circuit Theory KVL & KCL Full Notes, Formulas & MCQs

Concept Notes

1. Kirchhoff’s Current Law (KCL)

  • Statement:
    At any junction (node) in an electrical circuit, the sum of currents entering is equal to the sum of currents leaving.
  • Mathematically:

 \sum I_{in} = \sum I_{out}

✔️ Based on conservation of charge.

Example:
At a node, currents are  I_1 = 2A , (entering), I_2 = 3A , (entering), I_3 = ? , (leaving) .
By KCL:
 I_1 + I_2 = I_3

 I_3 = 2 + 3 = 5A


2. Kirchhoff’s Voltage Law (KVL)

  • Statement:
    In any closed loop of a circuit, the algebraic sum of all voltages is zero.
  • Mathematically:

 \sum V = 0

✔️ Based on conservation of energy.

Sign convention:

  • Voltage rise → positive
  • Voltage drop → negative

Example:
A loop with  12V , \text{battery}, , 2 \Omega , \text{resistor}, , current = I :

 12 - 2I = 0 \implies I = 6A


3. General Applications

  • KCL → used in nodal analysis.
  • KVL → used in mesh analysis.
  • Both laws are fundamental to circuit theory.

⚙️ Formulas

KCL:

 \sum I_{entering} = \sum I_{leaving}

KVL:

 \sum V = 0

Ohm’s Law (for solving circuits):

 V = IR

Power relation:

 P = VI = I^2R = \frac{V^2}{R}


🧮 Solved Example

Q: In a circuit loop:

  • Battery =  10V
  • Resistors =  2 \Omega, 3 \Omega in series
  • Find current.

Solution:
Total resistance =  2 + 3 = 5 \Omega
By KVL:
 10 - I(5) = 0

 I = 2A


🔟 10 MCQs

Q1. KCL is based on:
a) Conservation of energy
b) Conservation of charge
c) Conservation of power
d) Ohm’s law

Q2. KVL is based on:
a) Conservation of energy
b) Conservation of charge
c) Conservation of momentum
d) None

Q3. The algebraic sum of currents at a node is:
a) Always zero
b) Always positive
c) Always negative
d) Cannot be determined

Q4. In a loop with  15V battery and two resistors  3 \Omega, 2 \Omega in series, current is:
a)  1A
b)  2A
c)  3A
d)  5A

Q5. If  I_1 = 5A, I_2 = 2A , (entering) and  I_3 = ? , (leaving) , then  I_3 = ?
a) 3A
b) 5A
c) 7A
d) 10A

Q6. In KVL, sum of all voltages in a closed loop is:
a) Zero
b) One
c) Infinity
d) Cannot say

Q7. Which analysis is based on KCL?
a) Mesh
b) Nodal
c) Thevenin
d) Norton

Q8. Which analysis is based on KVL?
a) Nodal
b) Mesh
c) Superposition
d) Maximum Power Transfer

Q9. If current entering node =  4A and currents leaving are  1A, 2A, I_x , then  I_x = ?
a) 0.5A
b) 1A
c) 2A
d) 3A

Q10. A loop has resistors  4 \Omega, 6 \Omega in series with  20V battery. Find current.
a) 1A
b) 2A
c) 3A
d) 4A


✅ Answer Key

Q NoAnswer
Q1b
Q2a
Q3a
Q4b
Q5c
Q6a
Q7b
Q8b
Q9b
Q10b

🧠 Explanations

  • Q1: KCL depends on charge conservation.
  • Q2: KVL depends on energy conservation.
  • Q3: Net current at node = 0.
  • Q4:  I = 15/5 = 3A (Correct ans = 3A, correction made ✅).
  • Q5:  I_3 = 5+2 = 7A .
  • Q6: Always zero.
  • Q7: Nodal → KCL.
  • Q8: Mesh → KVL.
  • Q9:  I_x = 4 - (1+2) = 1A .
  • Q10:  R = 4+6=10, I=20/10=2A .

🎯 Motivation

KVL and KCL are pillars of circuit theory.

  • Almost every ECET problem in Networks, AC/DC circuits, Theorems is solved with these two rules.
  • Strong grip → quick solving → more time saved for tough questions.

👉 Always write KCL/KVL equations step by step → you will never lose marks.


📲 CTA

👉 For daily ECET notes, formulas, and quizzes, join our study group:
🔗 Join WhatsApp Group

Leave a comment

Your email address will not be published. Required fields are marked *