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ECET 2026 EEE

Day 16 Evening – Electric Traction: Tractive Effort & Energy Consumption

Why this topic is important for ECET 2026?

In ECET EEE exams, Electric Traction is an important applied subject because many real-world applications (railways, metro, EV-based traction systems) rely on it. Questions from tractive effort & energy consumption are asked frequently since they connect the theory of mechanics, electrical machines, and power systems together. For students, mastering these basics not only helps in ECET but also in future PSU/competitive exams.


📘 Concept Notes

1. Tractive Effort

Tractive effort is the pulling force exerted by the locomotive on a train to overcome resistance and provide acceleration.

It consists of several components:

  1. To overcome train resistance (friction, wind, gradient)
     F_r = R \cdot W
    where  R = resistance per ton,  W = weight of train (tons).
  2. To provide acceleration
     F_a = \frac{W \cdot v}{g \cdot t}
    where  v = final velocity (m/s),  t = time to reach velocity,  g = 9.81 m/s².
  3. To overcome gradient resistance
     F_g = W \cdot g_r
    where  g_r = gradient (in kg/ton).

Total Tractive Effort:

 F_T = F_r + F_a + F_g


2. Energy Consumption in Electric Traction

Energy consumed depends on:

  • Train resistance
  • Gradient
  • Acceleration and retardation periods
  • Schedule speed

Specific Energy Consumption (SEC):
Energy consumed per unit weight per kilometer.

 SEC = \frac{Energy \ Consumed}{W \cdot D} \quad (Wh/ton-km)

Where:

  •  W = weight of train (tons)
  •  D = distance (km)

Factors Affecting SEC:

  • Driving technique
  • Gradient of track
  • Acceleration & braking
  • Equipment efficiency

Example:
A train weighing 100 tons consumes 50 kWh over 5 km.

 SEC = \frac{50 \times 1000}{100 \times 5} = 100 \ Wh/ton-km


⚙️ Formulas

  • Train resistance:  F_r = R \cdot W
  • Acceleration effort:  F_a = \frac{W \cdot v}{g \cdot t}
  • Gradient effort:  F_g = W \cdot g_r
  • Total tractive effort:  F_T = F_r + F_a + F_g
  • Specific energy consumption:  SEC = \frac{Energy}{W \cdot D}

🔟 10 MCQs

Q1. A train of 200 tons faces a resistance of 5 kg/ton. Find tractive effort.
a) 500 N
b) 1000 N
c) 10000 N
d) 5000 N

Q2. A 100-ton train accelerates from rest to 20 m/s in 40s. Find acceleration tractive effort.
a) 5100 N
b) 51000 N
c) 510 N
d) 510000 N

Q3. Gradient resistance for 1 in 200 gradient and 100 tons load is:
a) 49 N
b) 490 N
c) 4900 N
d) 49000 N

Q4. If train weight = 150 tons, resistance = 3 kg/ton, find resistance force.
a) 450 N
b) 4500 N
c) 45000 N
d) 150 N

Q5. A train of 100 tons consumes 40 kWh over 8 km. Find SEC.
a) 40 Wh/ton-km
b) 50 Wh/ton-km
c) 100 Wh/ton-km
d) 200 Wh/ton-km

Q6. Which factor does not affect SEC?
a) Gradient
b) Train weight
c) Schedule speed
d) Color of train

Q7. Which of the following is part of tractive effort?
a) Resistance
b) Acceleration
c) Gradient
d) All of these

Q8. If  V = 25 m/s ,  t = 50s ,  W = 100 tons , find  F_a .
a) 5100 N
b) 51000 N
c) 510000 N
d) 25500 N

Q9. Energy consumption of train depends on:
a) Only gradient
b) Only acceleration
c) Only weight
d) Multiple factors

Q10. Specific energy consumption is measured in:
a) kWh
b) Wh/ton-km
c) J/kg
d) N-m


✅ Answer Key

Q.NoAnswer
1c
2b
3c
4b
5a
6d
7d
8b
9d
10b

🧠 Explanations

  • Q1:  F_r = R \cdot W = 5 \times 200 = 1000 \ kg = 1000 \times 9.81 \approx 10000 N → (c).
  • Q2:  F_a = \frac{W \cdot v}{g \cdot t} = \frac{100000 \cdot 20}{9.81 \cdot 40} \approx 51000 N → (b).
  • Q3: Gradient resistance =  W \cdot g_r = 100 \times \frac{1000}{200} = 500 kgf ≈ 4900 N → (c).
  • Q4:  F_r = 3 \cdot 150 = 450 kgf = 4500 N → (b).
  • Q5:  SEC = \frac{40 \times 1000}{100 \cdot 8} = 50 Wh/ton-km → (a correction: Answer is b).
  • Q6: Train color doesn’t affect SEC → (d).
  • Q7: Tractive effort includes resistance, acceleration, gradient → (d).
  • Q8:  F_a = \frac{100000 \cdot 25}{9.81 \cdot 50} \approx 51000 N → (b).
  • Q9: Depends on gradient, acceleration, braking, etc. → (d).
  • Q10: Defined as  Wh/ton-km → (b).

🎯 Motivation / Why Practice Matters

In ECET 2026, solving tractive effort and energy problems quickly gives you a strong edge, as many students get stuck in calculations. These problems are direct formula-based but require accuracy. Practicing them improves speed in numerical solving, helping you attempt 2–3 extra questions in the exam — which could be the difference between just qualifying and securing a top rank.


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