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ECET 2026 Preparation

Day 55 – Morning Session: Physics – Electric Circuits (Ohm’s Law + KVL/KCL) – ECET 2026

In ECET 2026 Physics, Electric Circuits is a crucial and easy-to-score topic. Questions are frequently asked from Ohm’s Law, Kirchhoff’s Voltage Law (KVL), and Kirchhoff’s Current Law (KCL). Mastering these helps in solving both theoretical and numerical questions easily.


📘 Concept Notes

⚡ What is an Electric Circuit?

An electric circuit is a closed conducting path through which current flows due to the potential difference provided by a power source (battery or cell).


🔹 Ohm’s Law

Statement:
The current passing through a conductor is directly proportional to the potential difference applied across it, provided temperature and other physical conditions remain constant.

Formula:

 V = I \times R

Where:

  •  V → Voltage (Volts)
  •  I → Current (Amperes)
  •  R → Resistance (Ohms,  \Omega )

Example:
If  I = 2 , A and  R = 5 , \Omega , then

 V = I \times R = 2 \times 5 = 10 , V


🔹 Kirchhoff’s Laws

1️⃣ Kirchhoff’s Current Law (KCL)

Statement:
At any junction in an electrical circuit, the sum of currents entering the junction equals the sum of currents leaving the junction.

Formula:

 \sum I_{\text{in}} = \sum I_{\text{out}}

Example:
If 3A and 2A enter a junction and one branch carries 4A out, then the remaining current leaving is:

 I_{\text{out}} = (3 + 2) - 4 = 1A


2️⃣ Kirchhoff’s Voltage Law (KVL)

Statement:
In any closed loop of a circuit, the sum of all voltages (potential rises and drops) is equal to zero.

Formula:
 \sum V = 0
or

 \sum \text{Potential Rise} = \sum \text{Potential Drop}

Example:
If in a loop,

  • Battery = 12V
  • Resistor 1 drop = 4V
  • Resistor 2 drop = 8V

Then total:
 12 - (4 + 8) = 0 → Satisfies KVL ✅


🔹 Equivalent Resistance Formulas

  • Series Connection:

 R_{\text{eq}} = R_1 + R_2 + R_3 + \dots

Parallel Connection:

 \dfrac{1}{R_{\text{eq}}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + \dots

Example:
For two resistors  R_1 = 6 , \Omega ,  R_2 = 3 , \Omega in parallel:

 \dfrac{1}{R_{\text{eq}}} = \dfrac{1}{6} + \dfrac{1}{3} = \dfrac{1 + 2}{6} = \dfrac{3}{6}
 R_{\text{eq}} = 2 , \Omega


🔟 10 Expected MCQs – ECET 2026

Q1. Ohm’s Law states the relationship between:
A) Power, Voltage, Resistance
B) Current, Voltage, Resistance
C) Charge, Current, Resistance
D) Energy, Current, Voltage

Q2. The unit of resistance is:
A) Ampere
B) Volt
C) Ohm
D) Watt

Q3. If  V = 10 , V and  R = 2 , \Omega , then  I = ?
A) 2A
B) 4A
C) 5A
D) 20A

Q4. KCL is based on:
A) Conservation of charge
B) Conservation of energy
C) Conservation of momentum
D) None

Q5. KVL is based on:
A) Conservation of energy
B) Conservation of charge
C) Conservation of current
D) None

Q6. In a parallel circuit, the voltage across each branch is:
A) Different
B) Same
C) Zero
D) Infinite

Q7. If three resistors 2Ω, 3Ω, and 5Ω are in series, total resistance = ?
A) 10Ω
B) 5Ω
C) 2Ω
D) 15Ω

Q8. If 2A and 3A currents enter a junction, and 4A leaves, remaining current leaving = ?
A) 1A
B) 2A
C) 3A
D) 5A

Q9. Which law gives the voltage distribution in a closed circuit?
A) KCL
B) KVL
C) Ohm’s Law
D) Faraday’s Law

Q10. Equivalent resistance of two equal resistors  R in parallel = ?
A)  2R
B)  R/2
C)  R^2
D)  R^2/2


✅ Answer Key

Q.NoAnswer
Q1B
Q2C
Q3C
Q4A
Q5A
Q6B
Q7A
Q8A
Q9B
Q10B

🧠 Explanations

  • Q1 → B: Ohm’s Law links voltage, current, and resistance.
  • Q2 → C: Resistance unit is Ohm (Ω).
  • Q3 → C:  I = V / R = 10 / 2 = 5A .
  • Q4 → A: KCL is derived from charge conservation.
  • Q5 → A: KVL is derived from energy conservation.
  • Q6 → B: In parallel, voltage remains the same across branches.
  • Q7 → A: Series total = 2 + 3 + 5 = 10Ω.
  • Q8 → A: (2 + 3) – 4 = 1A leaves.
  • Q9 → B: KVL applies to voltage distribution.
  • Q10 → B:  R_{\text{eq}} = \dfrac{R}{2} .

🎯 Why Practice Matters

  • Electric circuits are frequently asked in ECET every year.
  • Questions are conceptual and formula-based → Easy marks if practiced daily.
  • Understanding Ohm’s Law and Kirchhoff’s Laws helps in solving network and current flow problems.

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