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ECET 2026 Preparation

Day 37 – Morning Session: Physics – Reflection & Refraction – ECET 2026

In ECET 2026 Physics, Optics is an important unit. Reflection and Refraction concepts are repeatedly asked in exams. Understanding laws, formulas, and applications helps score direct marks.


📘 Concept Notes

🔹 Reflection of Light

  • Definition: The process of light bouncing back into the same medium after striking a surface.
  • Laws of Reflection:
    1. Angle of incidence  i = Angle of reflection  r .
    2. Incident ray, reflected ray, and normal all lie in the same plane.
  • Types of Reflection:
    • Regular reflection: From smooth surfaces (mirror).
    • Diffuse reflection: From rough surfaces.

🔹 Refraction of Light

  • Definition: Bending of light when it passes from one medium to another due to change in speed.
  • Laws of Refraction (Snell’s Law):

 n_1 \sin i = n_2 \sin r

Absolute Refractive Index:
 n = \dfrac{c}{v}
where  c = speed of light in vacuum,  v = speed of light in medium.

Relative Refractive Index:

 n_{21} = \dfrac{n_2}{n_1}

Critical Angle (C):
 \sin C = \dfrac{n_2}{n_1} , (when  n_1 > n_2 )

Total Internal Reflection (TIR):
Occurs when angle of incidence > critical angle, and light reflects completely inside the medium.


⚙️ Important Formulas

  1. Law of Reflection:

 i = r

Snell’s Law:

 n_1 \sin i = n_2 \sin r

Refractive Index:

 n = \dfrac{c}{v}

Relative Refractive Index:

 n_{21} = \dfrac{n_2}{n_1}

Critical Angle:

 \sin C = \dfrac{n_2}{n_1}


📐 Example Problems

Example 1:
A ray of light in air enters glass ( n = 1.5 ) at  i = 30^\circ . Find angle of refraction.

Using Snell’s law:
 1 \cdot \sin 30^\circ = 1.5 \cdot \sin r
 \sin r = \dfrac{0.5}{1.5} = 0.333

 r = 19.5^\circ

Example 2:
Critical angle of water ( n = 1.33 ) with air?

 \sin C = \dfrac{1}{1.33} = 0.75

 C = 48.75^\circ


🔟 10 Expected MCQs – ECET 2026

Q1. Angle of incidence = 40°, angle of reflection = ?
A) 20°
B) 40°
C) 50°
D) 60°

Q2. Snell’s law is expressed as:
A)  n_1 \cos i = n_2 \cos r
B)  n_1 \sin i = n_2 \sin r
C)  n_1 \tan i = n_2 \tan r
D) None

Q3. Refractive index  n = \dfrac{c}{v} , if  v = \dfrac{c}{2} , then  n = ?
A) 0.5
B) 1
C) 2
D) 4

Q4. Total Internal Reflection occurs when:
A)  i < C
B)  i = C
C)  i > C
D)  r > C

Q5. Critical angle is defined for light travelling:
A) From rarer to denser
B) From denser to rarer
C) From air to vacuum
D) None

Q6. If glass has  n = 1.5 , velocity of light in glass is:
A)  3 \times 10^8 , m/s
B)  2 \times 10^8 , m/s
C)  4.5 \times 10^8 , m/s
D)  1.5 \times 10^8 , m/s

Q7. Which phenomenon makes diamonds sparkle?
A) Diffraction
B) Dispersion
C) Total Internal Reflection
D) Polarization

Q8. The bending of stick in water is due to:
A) Reflection
B) Refraction
C) Diffraction
D) Interference

Q9. If  n_1 = 1.5 ,  n_2 = 1.0 , then  \sin C = ?
A) 0.5
B) 0.67
C) 1.5
D) 2.0

Q10. Which device uses TIR principle?
A) Lens
B) Prism
C) Mirror
D) Telescope


✅ Answer Key

Q.NoAnswer
Q1B
Q2B
Q3C
Q4C
Q5B
Q6B
Q7C
Q8B
Q9B
Q10B

🧠 Explanations

  • Q1 → B: Reflection law →  i = r .
  • Q2 → B: Snell’s law.
  • Q3 → C:  n = \dfrac{c}{v} = \dfrac{c}{c/2} = 2 .
  • Q4 → C: TIR when  i > C .
  • Q5 → B: Critical angle only for denser → rarer.
  • Q6 → B:  v = \dfrac{c}{n} = \dfrac{3 \times 10^8}{1.5} = 2 \times 10^8 .
  • Q7 → C: Sparkling of diamond = TIR.
  • Q8 → B: Bending = refraction.
  • Q9 → B:  \sin C = \dfrac{1}{1.5} = 0.67 .
  • Q10 → B: Prisms use TIR.

🎯 Why Practice Matters

  • Reflection and refraction are core optics topics in ECET.
  • Problems are formula-based and straightforward.
  • TIR-based questions appear almost every year.

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