Over 10 years we helping companies reach their financial and branding goals. Onum is a values-driven SEO agency dedicated.

CONTACTS
ECET 2026 CIVIL

Day 3 Hydraulics – Fluid Properties & Pressure Measurement (ECET 2026 Civil)

Why this topic is important for ECET

Fluids are the lifeline of civil engineering – from water supply systems, dams, canals, and pipelines to irrigation and hydrology. ECET 2026 Civil frequently tests fundamentals like density, viscosity, pressure head, Pascal’s law, and manometers. These are scoring topics, because once formulas are clear, answers come quickly.


📘 Concept Notes

1. Properties of Fluids

  • Density (ρ): Mass per unit volume.

 \rho = \frac{m}{V}

Specific Weight (γ): Weight per unit volume.

 \gamma = \rho g

Specific Gravity (SG): Ratio of density of fluid to density of water.

 SG = \frac{\rho}{\rho_w}

Viscosity (μ): Resistance to flow.
Shear stress in a Newtonian fluid:

 \tau = \mu \frac{du}{dy}

Kinematic Viscosity (ν):

 \nu = \frac{\mu}{\rho}

Compressibility (β): Reciprocal of bulk modulus.

 \beta = \frac{1}{K}


2. Pressure in Fluids

  • Pressure: Force per unit area.

 p = \frac{F}{A}

Hydrostatic Pressure: At depth h in a liquid:

 p = \rho g h

Pressure Head: Height of liquid column equivalent to given pressure.

 h_p = \frac{p}{\gamma}


3. Pascal’s Law

“Pressure applied at any point in a confined fluid is transmitted equally in all directions.”
This is the principle behind hydraulic jacks, lifts, and brakes.


4. Pressure Measurement Devices

  • Piezometer: Measures pressure head directly in terms of liquid column rise.
    Simple but limited to moderate pressures.
  • Manometer: Uses liquid columns to measure pressure differences.
    • Simple U-tube manometer – compares pressure with atmosphere.
    • Differential manometer – compares pressures at two points.
      Formula:

 p_A - p_B = (\rho_m - \rho_f) g h

Bourdon Gauge: Mechanical device, widely used in industry.


Example:
Water pressure at 5 m depth:

 p = \rho g h = 1000 \times 9.81 \times 5 = 49.05 , kPa


⚙️ Formulas

 \rho = \frac{m}{V}
 \gamma = \rho g
 SG = \frac{\rho}{\rho_w}
 \tau = \mu \frac{du}{dy}
 \nu = \frac{\mu}{\rho}
 \beta = \frac{1}{K}
 p = \frac{F}{A}
 p = \rho g h
 h_p = \frac{p}{\gamma}

 p_A - p_B = (\rho_m - \rho_f) g h


🔟 10 MCQs

Q1. The SI unit of viscosity is:
a) Ns/m²
b) kg/m²
c) N/m²
d) Pa/s

Q2. A liquid of SG = 1.2 has density = ? (water density = 1000 kg/m³)
a) 800 kg/m³
b) 1200 kg/m³
c) 1000 kg/m³
d) 1.2 kg/m³

Q3. Hydrostatic pressure at 10 m depth in water is:
a) 9.81 kPa
b) 49.05 kPa
c) 98.1 kPa
d) 100 kPa

Q4. Kinematic viscosity is:
a) μ × ρ
b) μ / ρ
c) ρ / μ
d) 1 / μ

Q5. Which law forms the basis of hydraulic machines?
a) Boyle’s law
b) Charles law
c) Pascal’s law
d) Bernoulli’s law

Q6. In a U-tube manometer containing mercury (ρ = 13,600 kg/m³) connected across water pipe, difference in mercury level = 0.2 m. Pressure difference = ?
a) 1.962 kPa
b) 19.62 kPa
c) 2.672 kPa
d) 26.72 kPa

Q7. Specific weight of water is approx:
a) 9.81 N/m³
b) 981 N/m³
c) 9810 N/m³
d) 1000 N/m³

Q8. A piezometer cannot measure:
a) Low pressures
b) High pressures
c) Negative pressures
d) Atmospheric pressures

Q9. Pressure head equivalent of 20 kPa in water is:
a) 2.04 m
b) 4.08 m
c) 20.4 m
d) 200 m

Q10. Differential manometer measures:
a) Absolute pressure
b) Gauge pressure
c) Difference of pressure between two points
d) Vacuum


✅ Answer Key

QAnswer
1d
2b
3c
4b
5c
6b
7c
8c
9b
10c

🧠 Explanations

  • Q1: SI unit of dynamic viscosity is Pa·s (same as Ns/m²) → (d).
  • Q2: SG = 1.2 → ρ = 1.2 × 1000 = 1200 kg/m³ → (b).
  • Q3: p = ρgh = 1000×9.81×10 = 98.1 kPa → (c).
  • Q4: ν = μ/ρ → (b).
  • Q5: Pascal’s law governs hydraulic lifts → (c).
  • Q6: Δp = (ρm – ρw)gh = (13600-1000)×9.81×0.2 ≈ 19.62 kPa → (b).
  • Q7: γ = 1000×9.81 = 9810 N/m³ → (c).
  • Q8: Piezometer cannot measure negative pressures (vacuum) → (c).
  • Q9: hp = p/γ = 20000/9810 ≈ 2.04 m → (b).
  • Q10: Differential manometer → pressure difference → (c).

🎯 Motivation / Why Practice Matters

Hydraulics is core Civil Engineering – examiners love asking pressure measurement and fluid properties because they are direct formula-based.
👉 In ECET 2026, speed matters. Solving such MCQs quickly gives you confidence and time for tougher questions.
👉 Consistent practice builds formula recall and reduces silly mistakes in units (Pa, kPa, m head).


📲 CTA

🔥 Join our WHATSAPP group for ECET 2026 updates and discussions →
👉 Join Here

Leave a comment

Your email address will not be published. Required fields are marked *