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ECET 2026 CIVIL

Day 1 Strength of Materials – Stress, Strain, Elastic Constants + Rectifiers (ECET 2026 Civil)

Concept Notes

Part A – Strength of Materials

1. Stress

  • Definition: Resistance offered by a body per unit area when an external force is applied.
  • Formula:
     \sigma = \frac{P}{A}
    where
    PPP = load, AAA = area.
  • Types: Tensile, Compressive, Shear.

Example: A rod of area 200 mm2200 \, mm^2200mm2 carries 40 kN load.

 \sigma = \frac{40 \times 10^3}{200 \times 10^{-6}} = 200 , MPa


2. Strain

  • Definition: Ratio of change in dimension to original dimension.

 \varepsilon = \frac{\Delta L}{L}

Example: A bar of 2 m elongates by 1 mm.

 \varepsilon = \frac{1}{2000} = 0.0005


3. Hooke’s Law

  • Within elastic limit,

 \sigma \propto \varepsilon \quad \Rightarrow \quad \sigma = E \varepsilon


4. Elastic Constants

  1. Young’s Modulus:

 E = \frac{\sigma}{\varepsilon}

Shear Modulus (Rigidity):

 G = \frac{\tau}{\gamma}

Bulk Modulus:

 K = \frac{p}{\Delta V/V}

Poisson’s Ratio:

 \mu = -\frac{\varepsilon_{lateral}}{\varepsilon_{longitudinal}}

Relations:
 E = 2G(1+\mu)
 E = 3K(1-2\mu)
 \frac{E}{G} = 2(1+\mu)

 \frac{E}{K} = 3(1-2\mu)


Part B – Rectifiers

Though an Electronics concept, basics are often asked for inter-disciplinary awareness.

1. Introduction

  • A rectifier converts AC → DC.
  • Used in power supplies for civil lab instruments, survey equipment, etc.

2. Half-Wave Rectifier (HWR)

  • Uses one diode.
  • Output: Pulsating DC.
  • Average DC value:

 V_{dc} = \frac{V_m}{\pi}

RMS value:

 V_{rms} = \frac{V_m}{2}

Rectification efficiency:

 \eta = \frac{0.406}{1} = 40.6%


3. Full-Wave Rectifier (FWR)

  • Uses two diodes (center-tap) or four diodes (bridge).
  • Output: Continuous DC pulses.
  • Average DC value:

 V_{dc} = \frac{2V_m}{\pi}

RMS value:

 V_{rms} = \frac{V_m}{\sqrt{2}}

Efficiency:

 \eta = 81.2%


4. Ripple Factor

  • Represents AC present in DC output.

 r = \frac{V_{rms(ac)}}{V_{dc}}

HWR:  r = 1.21

FWR:  r = 0.482


5. Peak Inverse Voltage (PIV)

  • Maximum reverse voltage a diode can withstand.
  • HWR:  PIV = V_m
  • FWR (center-tap):  PIV = 2V_m
  • Bridge Rectifier:  PIV = V_m

⚙️ Formulas

 \sigma = \frac{P}{A}
 \varepsilon = \frac{\Delta L}{L}
 \sigma = E \varepsilon
 E = \frac{\sigma}{\varepsilon}
 G = \frac{\tau}{\gamma}
 K = \frac{p}{\Delta V/V}
 \mu = -\frac{\varepsilon_{lateral}}{\varepsilon_{longitudinal}}
 E = 2G(1+\mu)
 E = 3K(1-2\mu)
 V_{dc(HWR)} = \frac{V_m}{\pi}
 V_{dc(FWR)} = \frac{2V_m}{\pi}
 V_{rms(HWR)} = \frac{V_m}{2}
 V_{rms(FWR)} = \frac{V_m}{\sqrt{2}}
 \eta_{HWR} = 40.6%
 \eta_{FWR} = 81.2%
 r_{HWR} = 1.21
 r_{FWR} = 0.482
 PIV_{HWR} = V_m
 PIV_{FWR} = 2V_m

 PIV_{Bridge} = V_m


🔟 10 MCQs

Q1. Stress is load per _____.
a) Length
b) Area
c) Volume
d) Modulus

Q2. A rod elongates by 0.5 mm for length 1 m. Find strain.
a) 0.0005
b) 0.005
c) 0.05
d) 0.5

Q3. Hooke’s law holds good up to:
a) Yield point
b) Elastic limit
c) Ultimate stress
d) Plastic range

Q4. A 100 mm² rod carries 20 kN. Stress = ?
a) 200 MPa
b) 100 MPa
c) 20 MPa
d) 2 MPa

Q5. Poisson’s ratio is:
a) Stress/Strain
b) Lateral strain/Longitudinal strain
c) Load/Area
d) Shear stress/Shear strain

Q6. Average DC output of Half-Wave Rectifier is:
a)  \frac{V_m}{2}
b)  \frac{V_m}{\pi}
c)  \frac{2V_m}{\pi}
d)  \frac{V_m}{\sqrt{2}}

Q7. Efficiency of Full-Wave Rectifier is:
a) 40.6%
b) 50%
c) 81.2%
d) 90%

Q8. Ripple factor of Half-Wave Rectifier is:
a) 1.21
b) 0.482
c) 1.0
d) 0.812

Q9. PIV for Bridge Rectifier = ?
a)  V_m
b)  2V_m
c)  V_m/2
d)  \sqrt{2} V_m

Q10. Relation between E and G is:
a)  E = G(1+\mu)
b)  E = 2G(1+\mu)
c)  E = 3G(1-2\mu)
d)  E = \frac{G}{1+\mu}


✅ Answer Key

QAnswer
1b
2a
3b
4a
5b
6b
7c
8a
9a
10b

🧠 Explanations

  • Q1: Stress = Load/Area → (b).
  • Q2: Strain = 0.5/1000 = 0.0005 → (a).
  • Q3: Hooke’s law valid up to elastic limit → (b).
  • Q4: Stress = 20×10³ / 100×10⁻⁶ = 200 MPa → (a).
  • Q5: Poisson’s ratio = lateral strain / longitudinal strain → (b).
  • Q6: HWR DC output = Vm/π → (b).
  • Q7: FWR efficiency = 81.2% → (c).
  • Q8: Ripple factor HWR = 1.21 → (a).
  • Q9: Bridge rectifier PIV = Vm → (a).
  • Q10: Correct relation: E = 2G(1+μ) → (b).

🎯 Motivation / Why Practice Matters

For ECET 2026, both Civil Core (SOM) and Basic Electronics (Rectifiers) may appear in mixed sections.

  • Stress–strain is a high-weightage topic forming base for RCC, Theory of Structures.
  • Rectifiers are small but scoring – formula-based questions often come.
    👉 If you master formulas + concepts, these become your “easy marks.”

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